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classes/sstate: break out function to get sstate manifest filename

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It is useful in a few different contexts to see which files have been
written out by an sstate task; break out a function that lets us get the
path to the manifest file easily.

(From OE-Core rev: 090196dd2d8f4306b34b239e78c39d37cc86034c)

Signed-off-by: Paul Eggleton <paul.eggleton@linux.intel.com>
Signed-off-by: Ross Burton <ross.burton@intel.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
This commit is contained in:
Paul Eggleton
2015-09-08 14:41:50 +01:00
committed by Richard Purdie
parent 2a05181d98
commit 3a9e230b7a
2 changed files with 14 additions and 5 deletions
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7
meta/classes/sstate.bbclass
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@@ -157,17 +157,14 @@ def sstate_add(ss, source, dest, d):
def sstate_install(ss, d):
import oe.path
import oe.sstatesig
import subprocess
sharedfiles = []
shareddirs = []
bb.utils.mkdirhier(d.expand("${SSTATE_MANIFESTS}"))
d2 = d.createCopy()
extrainf = d.getVarFlag("do_" + ss['task'], 'stamp-extra-info', True)
if extrainf:
d2.setVar("SSTATE_MANMACH", extrainf)
manifest = d2.expand("${SSTATE_MANFILEPREFIX}.%s" % ss['task'])
manifest, d2 = oe.sstatesig.sstate_get_manifest_filename(ss['task'], d)
if os.access(manifest, os.R_OK):
bb.fatal("Package already staged (%s)?!" % manifest)