Chris Larson 57044b9a62 Implement ??= operator ...

??= is a lazy, conditional assignment.  Whereas a ?= immediately assigns to
the variable if the variable has not yet been set, ??= does not apply the
default assignment until the end of the parse.  As a result, the final ??= for
a given variable is used, as opposed to the first as in ?=.

Note that the initial implementation relies upon finalise() to apply the
defaults, so a "bitbake -e" without specifying a recipe will not show the
defaults as set by ??=.  Moving application of the default into getVar adds
too large a performance hit.  We may want to revisit this later.

(Bitbake rev: 74f50fbca194c9c72bd2a540f4b9de458cb08e2d)

Signed-off-by: Chris Larson <chris_larson@mentor.com>
Signed-off-by: Richard Purdie <rpurdie@linux.intel.com>

2010-03-22 15:02:59 +00:00

..

manual

Implement ??= operator

2010-03-22 15:02:59 +00:00

bitbake.1

bitbake: Switch to bitbake-dev version (bitbake master upstream)

2010-01-20 18:46:02 +00:00

COPYING.GPL

bitbake: Sync with upstream.

2007-01-08 23:53:01 +00:00

COPYING.MIT

Initial population

2005-08-31 10:47:56 +00:00