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create-spdx: transform license list into a dict for faster lookups

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spdx-licenses.json contains an array of licenses objects. As we'll be
searching it often, convert that to a dictionary when we parse it.

(From OE-Core rev: 3405d9114ca9fe4ba820e0025c91670d1a5150b1)

Signed-off-by: Ross Burton <ross.burton@arm.com>
Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
This commit is contained in:
Ross Burton
2021-09-03 17:00:30 +01:00
committed by Richard Purdie
parent 2cca28cfde
commit 3c9102f3b6
1 changed files with 8 additions and 7 deletions
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15
meta/classes/create-spdx.bbclass
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@@ -44,7 +44,10 @@ python() {
return
with open(d.getVar("SPDX_LICENSES"), "r") as f:
d.setVar("SPDX_LICENSE_DATA", json.load(f))
data = json.load(f)
# Transform the license array to a dictionary
data["licenses"] = {l["licenseId"]: l for l in data["licenses"]}
d.setVar("SPDX_LICENSE_DATA", data)
}
def convert_license_to_spdx(lic, document, d):
@@ -55,9 +58,8 @@ def convert_license_to_spdx(lic, document, d):
def add_extracted_license(ident, name, text):
nonlocal document
for lic_data in license_data["licenses"]:
if lic_data["licenseId"] == ident:
return False
if ident in license_data["licenses"]:
return False
spdx_lic = oe.spdx.SPDXExtractedLicensingInfo()
spdx_lic.name = name
@@ -79,9 +81,8 @@ def convert_license_to_spdx(lic, document, d):
return "OR"
spdx_license = d.getVarFlag("SPDXLICENSEMAP", l) or l
for lic_data in license_data["licenses"]:
if lic_data["licenseId"] == spdx_license:
return spdx_license
if spdx_license in license_data["licenses"]:
return spdx_license
spdx_license = "LicenseRef-" + l