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create-spdx: Get SPDX-License-Identifier from source
This patch will read the begining of source files and try to find the SPDX-License-Identifier to populate the licenseInfoInFiles field for each source file. This does not populate licenseConcluded at this time, nor rolls it up to package level. We read as binary file since some source code seem to have some binary characters, the license is then converted to ascii strings. (From OE-Core rev: 51e5f328635eb022143178c3169bae719509697a) Signed-off-by: Saul Wold <saul.wold@windriver.com> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
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committed by
Richard Purdie
parent
76b3d141c0
commit
75f9785a2b
@@ -37,6 +37,23 @@ SPDX_SUPPLIER[doc] = "The SPDX PackageSupplier field for SPDX packages created f
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do_image_complete[depends] = "virtual/kernel:do_create_spdx"
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def extract_licenses(filename):
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import re
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lic_regex = re.compile(b'^\W*SPDX-License-Identifier:\s*([ \w\d.()+-]+?)(?:\s+\W*)?$', re.MULTILINE)
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try:
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with open(filename, 'rb') as f:
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size = min(15000, os.stat(filename).st_size)
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txt = f.read(size)
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licenses = re.findall(lic_regex, txt)
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if licenses:
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ascii_licenses = [lic.decode('ascii') for lic in licenses]
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return ascii_licenses
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except Exception as e:
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bb.warn(f"Exception reading {filename}: {e}")
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return None
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def get_doc_namespace(d, doc):
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import uuid
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namespace_uuid = uuid.uuid5(uuid.NAMESPACE_DNS, d.getVar("SPDX_UUID_NAMESPACE"))
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@@ -232,6 +249,11 @@ def add_package_files(d, doc, spdx_pkg, topdir, get_spdxid, get_types, *, archiv
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checksumValue=bb.utils.sha256_file(filepath),
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))
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if "SOURCE" in spdx_file.fileTypes:
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extracted_lics = extract_licenses(filepath)
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if extracted_lics:
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spdx_file.licenseInfoInFiles = extracted_lics
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doc.files.append(spdx_file)
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doc.add_relationship(spdx_pkg, "CONTAINS", spdx_file)
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spdx_pkg.hasFiles.append(spdx_file.SPDXID)
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