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license.bbclass: split incompatible license check into a helper function
This would help with checking incompatible licenses at do_rootfs step in image creation, where it is beneficial to pass the license string directly to the function. (From OE-Core rev: 8a0f342e4fc33b1aa53089b1de583d45d2951476) Signed-off-by: Alexander Kanavin <alex.kanavin@gmail.com> Signed-off-by: Richard Purdie <richard.purdie@linuxfoundation.org>
This commit is contained in:
committed by
Richard Purdie
parent
1d3ef1b9da
commit
f46b73658e
@@ -287,17 +287,7 @@ def incompatible_license_contains(license, truevalue, falsevalue, d):
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bad_licenses = expand_wildcard_licenses(d, bad_licenses)
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return truevalue if license in bad_licenses else falsevalue
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def incompatible_license(d, dont_want_licenses, package=None):
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"""
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This function checks if a recipe has only incompatible licenses. It also
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take into consideration 'or' operand. dont_want_licenses should be passed
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as canonical (SPDX) names.
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"""
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import oe.license
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license = d.getVar("LICENSE_%s" % package) if package else None
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if not license:
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license = d.getVar('LICENSE')
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def incompatible_pkg_license(d, dont_want_licenses, license):
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# Handles an "or" or two license sets provided by
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# flattened_licenses(), pick one that works if possible.
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def choose_lic_set(a, b):
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@@ -311,6 +301,19 @@ def incompatible_license(d, dont_want_licenses, package=None):
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return any(not oe.license.license_ok(canonical_license(d, l), \
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dont_want_licenses) for l in licenses)
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def incompatible_license(d, dont_want_licenses, package=None):
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"""
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This function checks if a recipe has only incompatible licenses. It also
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take into consideration 'or' operand. dont_want_licenses should be passed
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as canonical (SPDX) names.
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"""
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import oe.license
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license = d.getVar("LICENSE_%s" % package) if package else None
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if not license:
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license = d.getVar('LICENSE')
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return incompatible_pkg_license(d, dont_want_licenses, license)
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def check_license_flags(d):
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"""
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This function checks if a recipe has any LICENSE_FLAGS that
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